Who would win if they met today?
Match averages
Biggest wins
All meetings (2)
| Date | Home | Score | Away | Result | Competition |
|---|---|---|---|---|---|
| 14 Apr 2025 | Luxor | 0 - 2 | Asyut Cement | L | Egyptian Division 2 |
| 12 Jan 2024 | Luxor | 1 - 1 | Asyut Cement | D | Egypt Second Division B |
By venue
Competitions faced in
Egypt Second Division B
Egyptian Division 2
Year-by-year
| Year | Luxor | D | Asyut C… |
|---|---|---|---|
| 2025 | 0 | 0 | 1 |
| 2024 | 0 | 1 | 0 |
About this head-to-head
Luxor and Asyut Cement have met 2 times on record. Luxor lead with 0 wins, Asyut Cement have won 1 time and the two clubs have drawn 1 match between them. Their first recorded meeting was on 13 October 2023.
This page is the permanent head-to-head hub for Luxor vs Asyut Cement. Every future meeting between these two clubs will be added to this page automatically, so bookmark it for the latest results, biggest wins, venue records and competition breakdown. Visit the team pages for full squads, standings and upcoming fixtures: Luxor and Asyut Cement.
Across their recorded meetings, Luxor have found the net 1 time against Asyut Cement, while Asyut Cement have scored 3 times in reply — a combined 4 goals shared between the two sides. Their most recent fixture was played on 14 April 2025, the latest chapter in a rivalry stretching back to 2023. Follow every upcoming Luxor versus Asyut Cement clash on SportScore for live scores, starting lineups, minute-by-minute commentary and a head-to-head record that updates automatically once the full-time whistle blows.
Luxor vs Asyut Cement — head-to-head FAQ
How many times have Luxor and Asyut Cement played each other?
Luxor and Asyut Cement have met 2 times on record, with the first meeting on 13 October 2023.
Who has won more, Luxor or Asyut Cement?
Asyut Cement have the edge with 1 win to Luxor's 0, with 1 draw between them.
How many goals are scored when Luxor play Asyut Cement?
Their meetings produce 2.0 goals per game on average, and both teams have scored in 50% of them.